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%I #6 Oct 18 2017 04:44:40
%S 30,230,1309
%N First of the smallest n consecutive sphenic numbers A007304.
%C Every 4th consecutive number is divisible by 4 = 2*2 and therefore is not sphenic, so a(n) does not exist for n >= 4.
%H Wikipedia, <a href="https://en.wikipedia.org/wiki/Sphenic_number">Sphenic number</a>
%e 30 = 2*3*5 is the first spheric number, so a(1) = 30.
%e The first case of two consecutive sphenic numbers is 230 = 2*5*23 and 231 = 3*7*11, so a(2) = 230.
%e The first case of three is 1309 = 7*11*17, 1310 = 2*5*131, and 1311 = 3*19*23, so a(3) = 1309.
%Y Cf. A007304.
%K nonn,fini,full
%O 1,1
%A _Jonathan Sondow_, Oct 17 2017