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%I #17 Jul 12 2019 13:51:27
%S 1,17,1313,333089,207693089,268946253089,645510228813089,
%T 2643553803594573089,17342764866576345933089,
%U 173418555892594089945933089,2538940579958951120707545933089,52646414799433780559063261145933089
%N a(n) = Sum_{k=1..n} k!^4.
%C The only prime in this sequence is a(2) = 17 since a(n) is divisible by 13 for n >= 12 and there are no other primes with n < 12.
%H Seiichi Manyama, <a href="/A289945/b289945.txt">Table of n, a(n) for n = 1..144</a>
%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/FactorialSums.html">Factorial Sums</a>
%t Table[Sum[k!^4, {k, n}], {n, 12}]
%t Accumulate[(Range[15]!)^4] (* _Harvey P. Dale_, Jul 12 2019 *)
%o (PARI) a(n) = sum(k=1, n, k!^4); \\ _Michel Marcus_, Jul 16 2017
%Y Cf. A007489 (k!), A104344 (k!^2), A289946 (k!^6).
%K nonn
%O 1,2
%A _Eric W. Weisstein_, Jul 16 2017