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%I #6 Jun 26 2017 22:15:47
%S 3,6,7,10,12,13,16,19,21,22,25,28,31,32,33,35,36,39,42,45,46,49,50,52,
%T 53,54,56,57,60,63,66,67,70,72,73,76,78,79,80,81,83,84,85,87,88,91,94,
%U 97,98,101,103,104,107,110,112,113,116,119,120,121,123,124
%N Positions of 1 in A289007; complement of A289008.
%C Conjecture: a(n)/n -> 1.75..., and if m denotes this number, then -2 < m - a(n)/n < 0 for n >= 1.
%H Clark Kimberling, <a href="/A289009/b289009.txt">Table of n, a(n) for n = 1..10000</a>
%t z = 11; (* number of iterates *)
%t s = {0, 0}; w[0] = StringJoin[Map[ToString, s]];
%t w[n_] := StringReplace[w[n - 1], {"00" -> "0010", "01" -> "001", "10" -> "011"}]
%t TableForm[Table[w[n], {n, 0, 10}]]
%t st = ToCharacterCode[w[z]] - 48 (* A289007 *)
%t Flatten[Position[st, 0]] (* A289008 *)
%t Flatten[Position[st, 1]] (* A289009 *)
%Y Cf. A289007, A289008.
%K nonn,easy
%O 1,1
%A _Clark Kimberling_, Jun 26 2017
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