%I #4 Jun 04 2017 18:18:34
%S 3,4,5,9,12,13,14,18,19,20,24,27,28,29,33,36,37,38,42,43,44,48,51,52,
%T 53,57,58,59,63,66,67,68,72,75,76,77,81,82,83,87,90,91,92,96,99,100,
%U 101,105,106,107,111,114,115,116,120,121,122,126,129,130,131
%N Positions of 1 in A287790; complement of A287791.
%C -2 < n*r - a(n) < 2 for n >= 1, where r = (15 + 3*sqrt(5))/10.
%H Clark Kimberling, <a href="/A287792/b287792.txt">Table of n, a(n) for n = 1..10000</a>
%t s = Nest[Flatten[# /. {0 -> {0, 1}, 1 -> {0}}] &, {0}, 10] (* A003849 *)
%t w = StringJoin[Map[ToString, s]]
%t w1 = StringReplace[w, {"0" -> "001", "1" -> "110"}]
%t st = ToCharacterCode[w1] - 48 (* A287790 *)
%t Flatten[Position[st, 0]] (* A287791 *)
%t Flatten[Position[st, 1]] (* A287792 *)
%Y Cf. A287790, A287791.
%K nonn,easy
%O 1,1
%A _Clark Kimberling_, Jun 03 2017