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%I #4 May 18 2017 21:47:57
%S 3,6,8,11,13,16,19,21,24,26,29,32,34,37,39,42,44,47,50,52,55,57,60,63,
%T 65,68,70,73,75,78,81,83,86,88,91,94,96,99,101,104,107,109,112,114,
%U 117,119,122,125,127,130,132,135,138,140,143,145,148,150,153,156
%N Positions of 0 in A286987; complement of A286989.
%C a(n) - a(n-1) is in {2,3} for n>=2, and a(n)/n -> 4 - sqrt(8).
%H Clark Kimberling, <a href="/A286988/b286988.txt">Table of n, a(n) for n = 1..10000</a>
%e As a word, A286987 = 1101101011010110110101..., in which 0 is in positions 3,6,8,11,....
%t s = Nest[Flatten[# /. {0 -> 1, 1 -> {1, 1, 0}}] &, {1}, 11]; (* Sturmian word A080764 *)
%t w = StringJoin[Map[ToString, s]];
%t w1 = StringReplace[w, {"111" -> "1"}]
%t st = ToCharacterCode[w1] - 48 ; (* A286987 *)
%t Flatten[Position[st, 0]]; (* A286988 *)
%t Flatten[Position[st, 1]]; (* A286989 *)
%Y Cf. A080764, A286987, A286989.
%K nonn,easy
%O 1,1
%A _Clark Kimberling_, May 18 2017
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