%I
%S 2,4,5,7,9,12,14,15,17,19,22,24,26,27,29,32,34,36,37,39,42,44,46,47,
%T 49,51,54,56,57,59,61,64,66,68,69,71,74,76,78,79,81,84,86,88,89,91,93,
%U 96,98,99,101,103,106,108,109,111,113,116,118,120,121,123,126
%N Positions of 0 in A286752; complement of A286753.
%C 2n  a(n) is in {0,1} for n>=1.
%H Clark Kimberling, <a href="/A286753/b286753.txt">Table of n, a(n) for n = 1..10000</a>
%F a(n) = 1  A286754(n) for n >= 1.
%e As a word, A286752 = 10100101011010010101101001001..., in which 0 is in positions 2,4,5,7,9,12,...
%t s = Nest[Flatten[# /. {0 > {0, 1}, 1 > {0}}] &, {0}, 12]; (* A003849 *)
%t w = StringJoin[Map[ToString, s]];
%t w1 = StringReplace[w, {"010010" > ""}];
%t st = ToCharacterCode[w1]  48; (* A286752 *)
%t Flatten[Position[st, 0]]; (* A286753 *)
%t Flatten[Position[st, 1]]; (* A286754 *)
%Y Cf. A003849, A286752, A286754.
%K nonn,easy
%O 1,1
%A _Clark Kimberling_, May 14 2017
