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A285970 Positions of 0 in A285969; complement of A285971. 3

%I #4 May 09 2017 00:13:45

%S 1,3,4,5,7,9,10,12,13,15,16,17,19,20,22,23,25,27,28,29,31,33,34,36,37,

%T 39,40,42,44,45,46,48,49,51,52,53,55,57,58,60,61,63,64,65,67,68,70,71,

%U 73,75,76,77,79,80,82,83,84,86,88,89,91,92,94,95,97,99

%N Positions of 0 in A285969; complement of A285971.

%C Conjecture: a(n)/n -> 3/2.

%H Clark Kimberling, <a href="/A285970/b285970.txt">Table of n, a(n) for n = 1..10000</a>

%e As a word, A285969 = 0100010100100......, in which 0 is in positions 1,3,4,5,7,9,...

%t s = Nest[Flatten[# /. {0 -> {0, 1}, 1 -> {1, 0}}] &, {0}, 9] (* A010060 *)

%t w = StringJoin[Map[ToString, s]]

%t w1 = StringReplace[w, {"0110" -> "0"}]

%t st = ToCharacterCode[w1] - 48 (* A285969 *)

%t Flatten[Position[st, 0]] (* A285970 *)

%t Flatten[Position[st, 1]] (* A285971 *)

%Y Cf. A010060, A285969, A285971.

%K nonn,easy

%O 1,2

%A _Clark Kimberling_, May 08 2017

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Last modified June 20 03:21 EDT 2024. Contains 373512 sequences. (Running on oeis4.)