%I #4 May 09 2017 00:13:45
%S 1,3,4,5,7,9,10,12,13,15,16,17,19,20,22,23,25,27,28,29,31,33,34,36,37,
%T 39,40,42,44,45,46,48,49,51,52,53,55,57,58,60,61,63,64,65,67,68,70,71,
%U 73,75,76,77,79,80,82,83,84,86,88,89,91,92,94,95,97,99
%N Positions of 0 in A285969; complement of A285971.
%C Conjecture: a(n)/n > 3/2.
%H Clark Kimberling, <a href="/A285970/b285970.txt">Table of n, a(n) for n = 1..10000</a>
%e As a word, A285969 = 0100010100100......, in which 0 is in positions 1,3,4,5,7,9,...
%t s = Nest[Flatten[# /. {0 > {0, 1}, 1 > {1, 0}}] &, {0}, 9] (* A010060 *)
%t w = StringJoin[Map[ToString, s]]
%t w1 = StringReplace[w, {"0110" > "0"}]
%t st = ToCharacterCode[w1]  48 (* A285969 *)
%t Flatten[Position[st, 0]] (* A285970 *)
%t Flatten[Position[st, 1]] (* A285971 *)
%Y Cf. A010060, A285969, A285971.
%K nonn,easy
%O 1,2
%A _Clark Kimberling_, May 08 2017
