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%I #4 May 02 2017 10:50:54
%S 1,5,6,7,8,9,10,11,15,19,23,27,31,35,39,40,41,42,43,44,45,49,50,51,52,
%T 53,54,55,59,60,61,62,63,64,65,69,70,71,72,73,74,75,79,80,81,82,83,84,
%U 85,89,90,91,92,93,94,95,99,100,101,102,103,104,105,109
%N Positions of 1 in A285617; complement of A285618.
%C Conjecture: a(n)/n -> 2.
%H Clark Kimberling, <a href="/A285619/b285619.txt">Table of n, a(n) for n = 1..10000</a>
%e As a word, A285617 = 1000111111100010001001..., in which 1 is in positions 1,5,6,7,8,...
%t s = Nest[Flatten[# /. {0 -> {1, 1}, 1 -> {1, 0, 0, 0}}] &, {0}, 10] (* A285617 *)
%t Flatten[Position[s, 0]] (* A285618 *)
%t Flatten[Position[s, 1]] (* A285619 *)
%Y Cf. A285617, A285618.
%K nonn,easy
%O 1,2
%A _Clark Kimberling_, May 01 2017
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