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Positions of 1 in A284653; complement of A284654.
3

%I #4 Apr 08 2017 09:46:30

%S 2,3,5,7,8,11,12,14,15,17,18,21,22,24,26,27,29,31,32,35,36,38,40,41,

%T 43,45,46,49,50,52,53,55,56,59,60,62,64,65,68,69,71,73,74,77,78,80,81,

%U 83,84,87,88,90,92,93,95,97,98,101,102,104,105,107,108,111

%N Positions of 1 in A284653; complement of A284654.

%C Conjecture: -1 < n*sqrt(3) - a(n) < 2 for n >= 1.

%H Clark Kimberling, <a href="/A284655/b284655.txt">Table of n, a(n) for n = 1..10000</a>

%t s = Nest[Flatten[# /. {0 -> {1}, 1 -> {0, 1, 1, 0}}] &, {0}, 6] (* A284653 *)

%t Flatten[Position[s, 0]] (* A284654 *)

%t Flatten[Position[s, 1]] (* A284655 *)

%Y Cf. A284653, A284655, A284656.

%K nonn,easy

%O 1,1

%A _Clark Kimberling_, Apr 07 2017