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Numbers k such that A001222(k) = A001222(A003415(k)).
2

%I #10 Jan 27 2017 17:21:29

%S 4,8,9,14,21,25,26,27,32,33,36,38,46,48,49,50,54,57,62,69,74,80,85,88,

%T 93,94,99,100,106,121,125,128,129,133,134,145,156,166,169,176,177,178,

%U 205,207,213,216,217,218,226,230,237,240,242,243,248,249,252,253

%N Numbers k such that A001222(k) = A001222(A003415(k)).

%C Numbers k such that the number of prime divisors (counted with multiplicity) of k is equal to the number of prime divisors (counted with multiplicity) of the arithmetic derivative of k.

%H Colin Barker, <a href="/A281686/b281686.txt">Table of n, a(n) for n = 1..1000</a>

%o (PARI) arde(n) = sum(i=1, #f=factor(n)~, n/f[1, i]*f[2, i])

%o select(k->bigomega(k)==bigomega(arde(k)), vector(400, k, k+1))

%Y Cf. A001222, A003415, A209870, A281685.

%K nonn

%O 1,1

%A _Colin Barker_, Jan 27 2017