%I #20 May 13 2017 23:45:13
%S 0,2,1,3,4,5,7,9,121,10,21,123,125,127,129,141,11,143,13,145,1110,23,
%T 147,15,149,17,161,19,31,163,33,35,165,37,39,167,51,53,169,55,57,181,
%U 59,71,73,183,75,77,79,185,91,93,95,187,97,99,111,25,189,113,115,321,323,325,327,329,341,117,27,343,119,29,345
%N Each even term "t" of the sequence is followed by t odd terms and each even digit "k" of the sequence is followed by k odd digits.
%C After a(1) = 0, the sequence is always extended with the smallest integer not yet present which does not lead to a contradiction.
%C In a private mail to Eric Angelini, Lars Blomberg wrote about the b-file: "Only the even terms 0, 2, 4, 10, 1110, 12, 110, 6, 8, 2110, 2112, 2114, 14, 16, 18, 1112, 112, 2116 [are in this b-file]; so the sequence will continue from 2116 on with 2116 odd numbers, then an even one, etc."
%H Lars Blomberg, <a href="/A277677/b277677.txt">Table of n, a(n) for n = 1..8887</a>
%e There are respectively 0 odd terms after "0", then 2 odd terms after "2" (they are 1 and 3), then 4 odd terms after "4" (they are 5, 7, 9 and 121), then 10 odd terms after "10" (they are 221, 123, 125, 127, 129, 141, 11, 143, 13 and 145), etc.
%e But there are also respectively 0 odd digits after "0", then 2 odd digits after "2" (they are 1 and 3), then 4 odd digits after "4" (they are 4, 5, 7, 9 and 1), then 2 odd digits after the "2" of "121" (they are the last "1" of "121" and the starting "1" of "10"), then 0 odd digits after "0", then 2 odd digits after the "2" of "21" (they are the "1" of "21" and the starting "1" of 123), etc.
%Y Cf. A277623.
%K nonn,base
%O 1,2
%A _Eric Angelini_ and _Lars Blomberg_ Oct 26 2016
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