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A275637
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a(n) = (3^n-1)*(3^n-3)*(3^n+3)*(3^n-4)/5!.
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1
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0, 0, 24, 3588, 336336, 28456296, 2337415080, 190203890604, 15430065218592, 1250470878111312, 101305299883043256, 8206192556032342740, 664714105019032509168, 53842180220318324555448, 4361225716102504132538952, 353259529197097010875926396, 28614028512169065293302438464
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OFFSET
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0,3
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REFERENCES
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Turner, Zachary J., Bryson W. Finklea, and Terri Moore. "Combinatorial Approaches to Minimal Zero Sequences of Finite Abelian Groups, and a Surprising Connection." Preprint, Jan 09 2004.
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LINKS
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FORMULA
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a(n) = 121*a(n-1) - 3630*a(n-2) + 32670*a(n-3) - 88209*a(n-4) + 59049*a(n-5) for n > 4.
G.f.: x^2*(10692*x^2 - 684*x - 24)/((x - 1)*(3*x - 1)*(9*x - 1)*(27*x - 1)*(81*x - 1)). (End)
a(n) = (-36+5*3^(2+n)-5*9^n-5*27^n+81^n)/120. - Colin Barker, Aug 10 2016
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MATHEMATICA
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Table[With[{c=3^n}, ((c-1)(c-3)(c+3)(c-4))/120], {n, 0, 20}] (* or *) LinearRecurrence[ {121, -3630, 32670, -88209, 59049}, {0, 0, 24, 3588, 336336}, 20] (* Harvey P. Dale, Mar 09 2019 *)
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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