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%I #4 May 11 2016 15:12:59
%S 1,2,2,3,6,3,4,10,10,4,5,21,12,21,5,6,14,4,4,14,6,7,28,14,8,14,28,7,8,
%T 18,36,4,4,36,18,8,9,29,23,37,4,37,23,29,9,10,22,44,8,4,4,8,44,22,10,
%U 11,32,14,44,10,8,10,44,14,32,11,12,26,48,8,80,4,4,80,8,48,26,12,13,36,14,44
%N T(n,k)=Number of nXk 0..1 arrays with exactly n+k-2 having value 1 and no three 1s forming an isosceles triangle.
%C Table starts
%C ..1..2..3..4..5..6..7..8..9.10.11..12.13.14.15.16.17
%C ..2..6.10.21.14.28.18.29.22.32.26..36.30.40.34.44
%C ..3.10.12..4.14.36.23.44.14.48.14..52.14.56.16
%C ..4.21..4..8..4.37..8.44..8.44..0..34..4.44
%C ..5.14.14..4..4..4.10.80.37.56..4..12..0
%C ..6.28.36.37..4..8..4.22..0.34.32.203
%C ..7.18.23..8.10..4..4..4..2.48.24
%C ..8.29.44.44.80.22..4..8.16
%C ..9.22.14..8.37..0..2.16
%C .10.32.48.44.56.34.48
%C .11.26.14..0..4.32
%C .12.36.52.34.12
%C .13.30.14..4
%C .14.40.56
%C .15.34
%C .16
%H R. H. Hardin, <a href="/A272973/b272973.txt">Table of n, a(n) for n = 1..143</a>
%F Empirical for column k:
%F k=1: a(n) = 2*a(n-1) -a(n-2)
%F k=2: a(n) = a(n-1) +a(n-2) -a(n-3) for n>11
%e All solutions for n=3 k=4
%e ..0..0..0..1. .1..0..0..0. .1..1..1..0. .0..1..1..1
%e ..0..0..0..1. .1..0..0..0. .0..0..0..1. .1..0..0..0
%e ..1..1..1..0. .0..1..1..1. .0..0..0..1. .1..0..0..0
%K nonn,tabl
%O 1,2
%A _R. H. Hardin_, May 11 2016
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