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%I #21 May 11 2019 10:55:15
%S 354,1,12,2,1,7,2,4,3,1,6,2,2,1,1,3,7,1,1,3,2,1,37,2,3,2,1,1,1,7,19,3,
%T 1,6,1,3,1,2,54,2,15,4,1,1,2,1,3,1,33,2,15,1,4,1,1,1,1,3,41,1,1,3,3,2,
%U 1,4,4,1,9,7,2,4,1,2,23,7,3,7,1,1,20,9,7,62,1,8,24,2,3,1,1,2,1,1,3,2
%N Sequence arising from a mixed continued fraction for Pi: Pi = 22/(7+1/(354+1/(1+1/(12+...)))).
%C This is the continued fraction expansion of c = 22/Pi - 7.
%H J. W. Knoderer, <a href="http://www.mazes.com/pi/continuous-fractions-for-pi.htm">Continuous Fractions converging on the value of pi</a>, Mazes.com, 2016
%H J. W. Knoderer, <a href="http://www.mazes.com/pi/how-to-calculate-continuous-fraction-for-pi.pdf">Directions: How to calculate continuous fraction for Pi</a>, Mazes.com, 2016.
%H J. W. Knoderer, <a href="/A270782/a270782.jpg">Continuous Fraction for pi, 33 denominators</a>
%e The resulting successive approximations to Pi are:
%e Fraction 0: 22/7
%e Fraction 1: 22/(7+1/354)
%e Fraction 2: 22/(7+1/(354+1/1))
%e Fraction 3: 22/(7+1/(354+1/(1+1/12)))
%e To see fractions 4 to 35, see the links.
%p with(numtheory); Digits:=200:
%p c:=22/Pi - 7;
%p convert(evalf(c),confrac); # _N. J. A. Sloane_, Apr 05 2016
%K nonn,cofr
%O 0,1
%A _John William Knoderer_, Mar 22 2016
%E Edited by _N. J. A. Sloane_, Apr 05 2016
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