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 A270547 Denominators of r-Egyptian fraction expansion for sqrt(1/3), where r(k) = 1/(2k-1). 1
 2, 5, 19, 909, 866969, 1391730212321, 3778000141026848185401614, 40721846314736913560423097666261109869051562216449, 2752670766792898979726597410050364093079267724156167495561617776950485371872363605942870860465128310 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,1 COMMENTS Suppose that r is a sequence of rational numbers r(k) <= 1 for k >= 1, and that x is an irrational number in (0,1). Let f(0) = x, n(k) = floor(r(k)/f(k-1)), and f(k) = f(k-1) - r(k)/n(k). Then x = r(1)/n(1) + r(2)/n(2) + r(3)/n(3) + ... , the r-Egyptian fraction for x. See A269993 for a guide to related sequences. LINKS Clark Kimberling, Table of n, a(n) for n = 1..11 Eric Weisstein's World of Mathematics, Egyptian Fraction EXAMPLE sqrt(1/3) = 1/(1*2) + 1/(3*5) + 1/(5*19) + 1/(7*909) + ... MATHEMATICA r[k_] := 1/(2k-1); f[x_, 0] = x; z = 10; n[x_, k_] := n[x, k] = Ceiling[r[k]/f[x, k - 1]] f[x_, k_] := f[x, k] = f[x, k - 1] - r[k]/n[x, k] x = Sqrt(1/3); Table[n[x, k], {k, 1, z}] PROG (PARI) r(k) = 1/(2*k-1); f(k, x) = if (k==0, x, f(k-1, x) - r(k)/a(k, x); ); a(k, x=sqrt(1/3)) = ceil(r(k)/f(k-1, x)); \\ Michel Marcus, Apr 03 2016 CROSSREFS Cf. A269993, A005408, A020760. Sequence in context: A119563 A270398 A269997 * A177875 A187602 A260140 Adjacent sequences: A270544 A270545 A270546 * A270548 A270549 A270550 KEYWORD nonn,frac,easy AUTHOR Clark Kimberling, Apr 02 2016 STATUS approved

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Last modified January 30 15:21 EST 2023. Contains 359945 sequences. (Running on oeis4.)