%I #4 Jan 20 2016 07:07:54
%S 2,4,4,8,16,8,15,64,64,15,28,225,512,225,28,51,784,3375,3375,784,51,
%T 92,2601,21952,39330,21952,2601,92,164,8464,132651,451278,451278,
%U 132651,8464,164,290,26896,778688,4705642,9116396,4705642,778688,26896,290,509
%N T(n,k)=Number of nXk 0..1 arrays with every repeated value in every row and column greater than or equal to the previous repeated value.
%C Table starts
%C ...2......4.........8..........15.............28...............51
%C ...4.....16........64.........225............784.............2601
%C ...8.....64.......512........3375..........21952...........132651
%C ..15....225......3375.......39330.........451278..........4705642
%C ..28....784.....21952......451278........9116396........163879101
%C ..51...2601....132651.....4705642......163879101.......4977655636
%C ..92...8464....778688....47293550.....2818160392.....143643342651
%C .164..26896...4410944...453985015....45839624169....3885150758271
%C .290..84100..24389000..4225323881...718310821738..100631663710208
%C .509.259081.131872229.38217977443.10874476927778.2504347486850059
%H R. H. Hardin, <a href="/A267735/b267735.txt">Table of n, a(n) for n = 1..180</a>
%F Empirical for column k:
%F k=1: a(n) = 2*a(n-1) +a(n-2) -2*a(n-3) -a(n-4)
%F k=2: [order 9]
%F k=3: [order 16]
%F k=4: [order 42]
%e Some solutions for n=4 k=4
%e ..0..1..1..1....1..1..1..0....0..0..1..0....0..1..1..1....0..0..1..1
%e ..1..0..0..0....0..0..1..1....1..0..1..0....0..0..1..1....0..1..0..0
%e ..1..0..0..1....0..1..1..0....0..0..0..0....1..1..1..1....0..1..0..0
%e ..0..0..1..1....1..1..1..0....0..0..1..1....0..0..1..0....1..1..1..0
%Y Column 1 is A029907(n+1).
%K nonn,tabl
%O 1,1
%A _R. H. Hardin_, Jan 20 2016