%I #10 Dec 23 2015 14:14:57
%S 0,0,0,0,1,1,0,0,0,0,1,0,1,1,0,0,1,1,2,1,2,2,1,1,2,2,1,2,1,1,0,0,0,0,
%T 0,0,0,0,2,0,0,0,2,0,2,2,1,0,0,0,2,0,2,2,1,0,2,2,1,2,1,1,0,0,1,1,1,1,
%U 1,1,3,1,1,1,3,1,3,3,2,1,1,1,3,1,3,3
%N a(n) = A070939(n) mod A000120(n), where A070939(n) is the binary length of n and A000120(n) is the binary weight of n.
%H Michael De Vlieger, <a href="/A265918/b265918.txt">Table of n, a(n) for n = 1..10000</a>
%t Table[Mod[IntegerLength[n, 2], Total@ IntegerDigits[n, 2]], {n, 120}] (* _Michael De Vlieger_, Dec 21 2015 *)
%o (Python)
%o for n in range(1, 88): print str((len(bin(n))-2) % bin(n).count('1'))+',',
%o (PARI) a(n) = #binary(n) % hammingweight(n); \\ _Michel Marcus_, Dec 19 2015
%Y Cf. A000120, A070939, A135941, A199238, A265917.
%K nonn,base
%O 1,19
%A _Alex Ratushnyak_, Dec 18 2015
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