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A265750 Prime factorization representation of polynomials defined recursively by p(0,x)=1 and for n>0: p(n,x) = x*p(n-1,x) + 4n+2. (See A192750). 6

%I #9 Dec 18 2015 11:34:30

%S 2,192,3732480,105815808000000,15845956399848960000000000,

%T 64521196676588557133336908800000000000000,

%U 11596208520592232147315615803672416545196288000000000000000000,254410805372253907145905144265082090216385314644252349615132618240000000000000000000000

%N Prime factorization representation of polynomials defined recursively by p(0,x)=1 and for n>0: p(n,x) = x*p(n-1,x) + 4n+2. (See A192750).

%H Antti Karttunen, <a href="/A265750/b265750.txt">Table of n, a(n) for n = 0..10</a>

%F a(0) = 2; for n >= 1, a(n) = A003961(a(n-1)) * 2^((4*n)+2).

%F Other identities. For all n >= 1:

%F A192750(n) = A265752(a(n)).

%F A192751(n) = A265753(a(n)).

%o (PARI)

%o A003961(n) = my(f = factor(n)); for (i=1, #f~, f[i, 1] = nextprime(f[i, 1]+1)); factorback(f); \\ Using code of Michel Marcus

%o A265750(n) = if(0==n, 2, A003961(A265750(n-1)) * 2^((4*n)+2));

%o for(n=0, 10, write("b265750.txt", n, " ", A265750(n)));

%o (Scheme) (definec (A265750 n) (if (zero? n) 2 (* (A003961 (A265750 (- n 1))) (A000079 (+ 2 (* 4 n))))))

%Y Cf. A003961, A192750, A192751, A206296, A265752, A265753.

%K nonn

%O 0,1

%A _Antti Karttunen_, Dec 15 2015

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Last modified April 19 17:51 EDT 2024. Contains 371797 sequences. (Running on oeis4.)