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%I #7 Jun 20 2015 14:43:04
%S 0,1,2,98,775
%N Numbers n such that cyclotomic polynomial value Phi(9,n!) is prime.
%C All values correspond to certified primes.
%C a(6) > 5944.
%e 2 is in the sequence because Phi(9,2!) = 1 + 2^3 + 2^6 = 73 is prime.
%t Select[Range[0, 5944], PrimeQ[Cyclotomic[9, #!]] &]
%Y Cf. A002981, A002982, A046029, A200906.
%K nonn,more
%O 1,3
%A _Robert Price_, May 27 2015
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