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a(n) = A208570(n)/n.
2

%I #15 May 22 2015 04:36:08

%S 2,3,2,3,2,2,2,3,2,3,2,5,2,3,2,3,2,2,2,3,2,3,2,5,2,3,2,3,2,2,2,3,2,3,

%T 2,5,2,3,2,3,2,2,2,3,2,3,2,5,2,3,2,3,2,2,2,3,2,3,2,7,2,3,2,3,2,2,2,3,

%U 2,3,2,5,2,3,2,3,2,2,2,3,2,3,2,5

%N a(n) = A208570(n)/n.

%C The prime p that minimizes p^(1+nu_p(n)), where nu_p(n) is the p-adic order of n.

%C It satisfies p^(1+nu_p(n)) = A007978(n).

%H Robert Israel, <a href="/A258115/b258115.txt">Table of n, a(n) for n = 1..10000</a>

%p Primes:= select(isprime,[2,seq(2*i+1,i=1..100)]):

%p seq(Primes[min[index](map(p -> p^(1+padic[ordp](n,p)), Primes))],n=1..200);

%t Table[(LCM[n, Min[Complement[Range[n+1], Divisors[n]]]]/n), {n, 100}] (* _Vincenzo Librandi_, May 21 2015 *)

%o (Haskell)

%o a258115 n = a208570 n `div` n -- _Reinhard Zumkeller_, May 22 2015

%Y Cf. A007978, A208570.

%K nonn

%O 1,1

%A _Robert Israel_, May 20 2015