%I #15 Apr 16 2015 15:27:11
%S 0,1,1,2,1,2,1,4,2,2,1,3,1,2,2,5,1,3,1,3,2,2,1,5,2,2,4,3,1,3,1,6,2,2,
%T 2,4,1,2,2,5,1,3,1,3,3,2,1,6,2,3,2,3,1,5,2,5,2,2,1,4,1,2,3,8,2,3,1,3,
%U 2,3,1,6,1,2,3,3,2,3,1,6,5,2,1,4,2,2,2,5,1,4,2,3,2,2,2,7,1,3,3,4
%N a(n) = log_3 (A256689(n)).
%C a(n) is the logarithm to the base 3 of the denominator of the Dirichlet series of zeta(s)^(1/3). For details, see A256689.
%H Wolfgang Hintze, <a href="/A257089/b257089.txt">Table of n, a(n) for n = 1..500</a>
%F 3^a(n) = A256689(n). a(n) = A007949(A256689(n)).
%Y Cf. A046645 (k = 2, log_2), A257089 (k = 3, log_3), A257090 (k = 4, log_2), A257091 (k = 5, log_5).
%K nonn
%O 1,4
%A _Wolfgang Hintze_, Apr 16 2015