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A256608 Least common eventual period of a^(2^k) mod n for all a. 5

%I #23 Dec 14 2016 13:21:44

%S 1,1,1,1,1,1,2,1,2,1,4,1,2,2,1,1,1,2,6,1,2,4,10,1,4,2,6,2,3,1,4,1,4,1,

%T 2,2,6,6,2,1,4,2,6,4,2,10,11,1,6,4,1,2,12,6,4,2,6,3,28,1,4,4,2,1,2,4,

%U 10,1,10,2,12,2,6,6,4,6,4,2,12,1,18,4,20,2,1,6

%N Least common eventual period of a^(2^k) mod n for all a.

%C a(n) is a divisor of phi(phi(n)) (A010554).

%H Ivan Neretin, <a href="/A256608/b256608.txt">Table of n, a(n) for n = 1..10000</a>

%H Haifeng Xu, <a href="http://arxiv.org/abs/1601.06509">The largest cycles consist by the quadratic residues and Fermat primes</a>, arXiv:1601.06509 [math.NT], 2016.

%F a(n) = A007733(A002322(n)).

%F a(prime(n)) = A037178(n). - _Michel Marcus_, Jan 27 2016

%e In other words, eventual period of {0..n-1} under the map x -> x^2 mod n.

%e For example, with n=10 the said map acts as follows. Read down the columns: the column headed 2 for example means that (repeatedly squaring mod 10), 2 goes to 4 goes to 16 = 6 (mod 10) goes to 36 = 6 mod 10 --- and has reached a fixed point.

%e 0 1 2 3 4 5 6 7 8 9

%e 0 1 4 9 6 5 6 9 4 1

%e 0 1 6 1 6 5 6 1 6 1

%e 0 1 6 1 6 5 6 1 6 1

%e and thus every number reaches a fixed point. This means the eventual common period is 1, hence a(10)=1.

%t a[n_] := With[{lambda = CarmichaelLambda[n]}, MultiplicativeOrder[2, lambda / (2^IntegerExponent[lambda, 2])]]; Table[a[n], {n, 1, 100}] (* _Jean-François Alcover_, Jan 28 2016 *)

%o (PARI) rpsi(n) = lcm(znstar(n)[2]); \\ A002322

%o pb(n) = znorder(Mod(2, n/2^valuation(n, 2))); \\ A007733

%o a(n) = pb(rpsi(n)); \\ _Michel Marcus_, Jan 28 2016

%Y Cf. A001146, A002322, A002326, A007733, A010554, A037178.

%Y First differs from A256607 at n=43.

%Y LCM of entries in row n of A279185.

%K nonn

%O 1,7

%A _Ivan Neretin_, Apr 04 2015

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