%I
%S 512,2703,2703,12730,15848,12730,55904,95110,95110,55904,221858,
%T 522294,748444,522294,221858,833037,2691838,5525547,5525547,2691838,
%U 833037,2977462,13380696,37573674,52855290,37573674,13380696,2977462,10225464
%N T(n,k)=Number of (n+2)X(k+2) 0..1 arrays with every 3X3 subblock sum of four medians of central row, central column, diagonal and antidiagonal nondecreasing horizontally and vertically
%C Table starts
%C ......512.......2703.......12730.........55904.........221858...........833037
%C .....2703......15848.......95110........522294........2691838.........13380696
%C ....12730......95110......748444.......5525547.......37573674........247721056
%C ....55904.....522294.....5525547......52855290......463784139.......4043573364
%C ...221858....2691838....37573674.....463784139.....5252066348......59733054453
%C ...833037...13380696...247721056....4043573364....59733054453.....913402797416
%C ..2977462...64480314..1555784900...32502418874...617600165386...12435035618491
%C .10225464..303930381..9507310251..255406348232..6259013485112..165816689112144
%C .34028886.1410213321.56427672574.1922225812231.60421295621544.2098552515955862
%H R. H. Hardin, <a href="/A254819/b254819.txt">Table of n, a(n) for n = 1..179</a>
%F Empirical for column k:
%F k=1: [linear recurrence of order 58] for n>59
%e Some solutions for n=2 k=4
%e ..0..0..0..1..0..1....0..0..0..0..0..0....0..0..0..0..1..1....0..0..0..0..1..1
%e ..1..0..0..1..0..1....1..0..0..0..1..0....1..0..0..1..1..1....0..0..0..1..0..1
%e ..0..0..0..0..0..0....0..0..1..0..1..0....0..0..1..0..1..0....0..0..0..0..0..0
%e ..1..0..0..1..0..0....1..0..0..0..1..0....1..1..1..1..0..1....1..0..0..1..0..1
%Y Column 1 is A254505
%K nonn,tabl
%O 1,1
%A _R. H. Hardin_, Feb 08 2015
