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Number of length 4+4 0..n arrays with every five consecutive terms having four times some element equal to the sum of the remaining four
1

%I #4 Nov 03 2014 09:59:36

%S 2,53,164,485,1620,3981,9026,18009,31276,53643,83648,124019,177426,

%T 246495,341802,460879,604888,778121,983998,1248361,1556940,1913895,

%U 2325318,2796619,3361158,3997715,4713400,5516083,6407962,7439621,8580604

%N Number of length 4+4 0..n arrays with every five consecutive terms having four times some element equal to the sum of the remaining four

%C Row 4 of A249656

%H R. H. Hardin, <a href="/A249660/b249660.txt">Table of n, a(n) for n = 1..187</a>

%e Some solutions for n=6

%e ..5....3....0....3....0....4....4....3....6....6....0....6....0....3....3....5

%e ..0....0....5....6....6....4....0....1....0....1....0....0....3....1....5....6

%e ..5....4....0....1....1....5....1....4....2....3....3....3....0....3....6....4

%e ..3....3....3....4....2....4....3....5....2....2....2....4....5....5....5....2

%e ..2....5....2....1....1....3....2....2....0....3....5....2....2....3....6....3

%e ..5....3....5....3....0....4....4....3....6....1....0....1....0....3....3....5

%e ..0....0....0....6....1....4....5....6....0....6....5....5....3....1....5....1

%e ..5....4....5....1....1....5....1....4....2....3....3....3....5....3....6....4

%K nonn

%O 1,1

%A _R. H. Hardin_, Nov 03 2014