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Number of length n+4 0..5 arrays with every five consecutive terms having four times some element equal to the sum of the remaining four
1

%I #5 Nov 03 2014 09:53:20

%S 1046,1218,1408,1620,1858,2126,2590,3132,3764,4498,5346,6778,8510,

%T 10594,13082,16026,20906,26980,34468,43590,54566,72558,95404,124036,

%U 159386,202386,272426,362494,476538,618506,792346,1074554,1440204,1906020

%N Number of length n+4 0..5 arrays with every five consecutive terms having four times some element equal to the sum of the remaining four

%C Column 5 of A249656

%H R. H. Hardin, <a href="/A249653/b249653.txt">Table of n, a(n) for n = 1..210</a>

%F Empirical: a(n) = a(n-1) +9*a(n-5) -9*a(n-6) -26*a(n-10) +26*a(n-11) +25*a(n-15) -25*a(n-16) -a(n-20) +a(n-21) -2*a(n-25) +2*a(n-26)

%e Some solutions for n=6

%e ..3....4....1....4....4....0....5....2....4....3....3....5....0....0....0....4

%e ..5....2....1....2....0....4....2....2....2....3....2....5....0....5....0....2

%e ..5....5....2....1....3....3....0....0....0....0....2....3....0....2....2....3

%e ..3....5....3....0....2....5....1....3....2....4....4....4....4....3....5....2

%e ..4....4....3....3....1....3....2....3....2....5....4....3....1....0....3....4

%e ..3....4....1....4....4....5....0....2....4....3....3....0....0....5....0....4

%e ..5....2....1....2....0....4....2....2....2....3....2....5....0....0....5....2

%e ..0....5....2....1....3....3....5....5....0....0....2....3....0....2....2....3

%e ..3....5....3....5....2....0....1....3....2....4....4....4....4....3....0....2

%e ..4....4....3....3....1....3....2....3....2....5....4....3....1....0....3....4

%K nonn

%O 1,1

%A _R. H. Hardin_, Nov 03 2014