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%I #9 Feb 03 2015 12:58:38
%S 0,1,2896,306827,8388608,109183006,888667667,5231514822,24296003999,
%T 94143178827,316227766016,946271759726,2573856496961,6461726194556,
%U 15152085430295,33500360392119,70368744177664,141306648466586
%N Integer part of square root of A010811(n) = n^23.
%H Karl V. Keller, Jr., <a href="/A248109/b248109.txt">Table of n, a(n) for n = 0..1000</a>
%F a(n) = floor(sqrt(n^23)).
%e for n = 4, floor(sqrt(n^23)) = 8388608.
%t IntegerPart[Sqrt[#]]&/@(Range[0,20]^23) (* _Harvey P. Dale_, Feb 03 2015 *)
%o (Python)
%o from decimal import *
%o getcontext().prec = 100
%o for n in range(0,1001): print n, int(Decimal(n**23).sqrt())
%o (PARI) a(n)=sqrtint(n^23) \\ _Charles R Greathouse IV_, Oct 01 2014
%Y Cf. A010811 (n^23).
%K nonn,easy
%O 0,3
%A _Karl V. Keller, Jr._, Oct 01 2014
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