%I
%S 2,5,8,10,13,16,19,22,24,27,30,33,35,38,41,44,47,49,52,55,58,61,63,66,
%T 69,72,74,77,80,83,86,88,91,94,97,100,102,105,108,111,113,116,119,122,
%U 125,127,130,133,136,138,141,144,147,150,152,155,158,161,164
%N Numbers k such that A247778(k+1)  A247778(k) = 2.
%C Complement of A247779.
%H Clark Kimberling, <a href="/A247780/b247780.txt">Table of n, a(n) for n = 1..1000</a>
%e The values of e  (1 + 1/k)^k for k = 1..8 are approximately 0.718282, 0.468282, 0.347911, 0.276876, 0.229962, 0.196655, 0.171782, 0.152497, so that the first 6 terms of A247778 are 1,2,4,5,6,8, and the first three terms of A247780 are 1,3,4.
%t z = 600; f[n_] := f[n] = Select[Range[z], E  (1 + 1/#)^# < 1/n &, 1];
%t u = Flatten[Table[f[n], {n, 1, z}]] (*A247778*)
%t d1 = Flatten[Position[Differences[u], 1]] (*A247779*)
%t d2 = Flatten[Position[Differences[u], 2]] (*A247780*)
%Y Cf. A247778, A247779.
%K nonn,easy
%O 1,1
%A _Clark Kimberling_, Sep 23 2014
