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%I #5 Nov 16 2016 12:30:07
%S 16,75,242,573,1162,2187,3792,6015,9262,13157,18834,25837,35450,46475,
%T 60540,75733,95800,118569,147542,178703,213796,254841,303516,356489,
%U 421292,488619,562216,645721,742110,844421,961734,1082763,1224050
%N Number of length 4 0..n arrays with each partial sum starting from the beginning no more than two standard deviations from its mean
%C Row 4 of A244832
%H R. H. Hardin, <a href="/A244835/b244835.txt">Table of n, a(n) for n = 1..210</a>
%e Some solutions for n=10
%e ..7....8....4....0....1....8....0....2....2....3....6....4....5....7....7....9
%e ..7....3....6....4....7....5....3....8....3....4....1...10....5....0....1....6
%e ..3....6....0....8....8....1...10....6...10....1....7....3....8....0....3....8
%e ..1...10....8....6....4....5....3...10....7....7....1....2....0....3....5....3
%K nonn
%O 1,1
%A _R. H. Hardin_, Jul 06 2014