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%I #5 Nov 16 2016 12:30:07
%S 5,25,117,573,2833,13785,68311,339839,1677913,8250991,41042033,
%T 202864491,1010570485,5010240575,24786030031,123527459073,
%U 613216664859,3059004849315,15214286790073,75565229450871,374920922490613
%N Number of length n 0..4 arrays with each partial sum starting from the beginning no more than two standard deviations from its mean
%C Column 4 of A244832
%H R. H. Hardin, <a href="/A244828/b244828.txt">Table of n, a(n) for n = 1..210</a>
%e Some solutions for n=7
%e ..0....3....3....2....2....3....3....3....2....3....3....4....2....0....2....1
%e ..3....2....4....2....3....1....3....1....1....2....1....1....0....3....0....0
%e ..1....3....1....1....4....4....3....2....3....2....0....3....2....2....1....2
%e ..2....4....0....1....1....4....0....0....3....3....1....4....4....2....4....3
%e ..2....2....4....1....0....1....3....0....0....0....3....1....4....0....4....3
%e ..4....3....0....1....3....2....3....0....1....4....0....4....3....2....1....2
%e ..0....3....3....2....1....4....3....2....0....2....3....4....0....3....0....2
%K nonn
%O 1,1
%A _R. H. Hardin_, Jul 06 2014
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