%I #21 Jul 02 2014 17:10:27
%S 11,22,33,44,55,66,77,88,99,111,222,333,335,444,534,551,555,579,589,
%T 666,682,777,888,954,956,999,1102,1111,2138,2204,2222,2246,2649,3190,
%U 3333,4354,4408,4428,4444,5332,5376,5555,5644,5925,6294,6666,6933,7480,7528
%N Consider a number n with m decimal digits, m>1. The sequence lists the numbers n such that the prefix of length m1 and the suffix of length m1 both have the same sum of divisors.
%C Let x(0)x(1)... x(q1)x(q) denote the decimal expansion of a number n. The sequence lists the numbers n such that sigma(p) = sigma(s) where p is the prefix x(0)x(1)... x(q1) and s is the suffix x(1)... x(q1)x(q).
%e 5376 is in the sequence because sigma(537) = sigma(376) = 720.
%p with(numtheory):
%p for n from 10 to 10000 do:
%p x:=convert(n, base, 10):n1:=nops(x):
%p s1:=sum('x[i]*10^(i1) ', 'i'=1..n11):
%p s2:=(nirem(n,10))/10:
%p x1:=sigma(s1):x2:=sigma(s2):
%p if x1 = x2
%p then
%p printf(`%d, `, n):
%p else
%p fi:
%p od:
%Y Cf. A244282, A244283.
%K nonn,base
%O 1,1
%A _Michel Lagneau_, Jun 27 2014
