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a(n) = 252 * n.
0

%I #30 May 05 2024 18:06:12

%S 0,252,504,756,1008,1260,1512,1764,2016,2268,2520,2772,3024,3276,3528,

%T 3780,4032,4284,4536,4788,5040,5292,5544,5796,6048,6300,6552,6804,

%U 7056,7308,7560,7812,8064,8316,8568,8820,9072,9324,9576,9828,10080,10332,10584,10836,11088,11340

%N a(n) = 252 * n.

%C As lcm(1,2,3,...,9) = 2520, 10*a(n) + k is divisible by each k from 1 through 9.

%H <a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (2,-1).

%F From _Elmo R. Oliveira_, Apr 16 2024: (Start)

%F G.f.: 252*x/(x-1)^2.

%F E.g.f.: 252*x*exp(x).

%F a(n) = 2*a(n-1) - a(n-2) for n >= 2.

%F a(n) = 7*A044102(n) = 9*A135628(n) = 12*A008603(n) = 14*A008600(n) = 18*A008596(n) = 21*A008594(n) = 28*A008591(n) = 36*A008589(n) = 252*A001477(n). (End)

%t 252*Range[0, 49] (* _Alonso del Arte_, May 17 2014 *)

%o (PARI) for(n=0,50,print(252*n))

%Y Cf. A001477, A008600, A008603, A008589, A008591, A008594, A008596.

%Y Cf. A044102, A135628.

%K nonn,easy,less

%O 0,2

%A _Derek Orr_, May 17 2014