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Integer part of square root of A010809(n) = n^21.
1

%I #38 Dec 17 2024 15:18:00

%S 0,1,1448,102275,2097152,21836601,148111277,747359260,3037000499,

%T 10460353203,31622776601,86024705429,214488041413,497055861119,

%U 1082291816449,2233357359474,4398046511104,8312155792152,15148209527700,26724698233906

%N Integer part of square root of A010809(n) = n^21.

%H Karl V. Keller, Jr., <a href="/A242038/b242038.txt">Table of n, a(n) for n = 0..1000</a>

%F a(n) = floor(sqrt(n^21)).

%e For n = 4, floor(sqrt(4^21)) = 2097152.

%o (Python)

%o from decimal import *

%o getcontext().prec = 100

%o for n in range(0,1001): print(int(Decimal(n**21).sqrt()))

%o (PARI) a(n) = sqrtint(n^21) \\ _Michel Marcus_, Oct 01 2014

%Y Cf. A010809 (n^21).

%K nonn

%O 0,3

%A _Karl V. Keller, Jr._, Oct 01 2014