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A237721 Number of primes p <= n with floor( sqrt(n-p) ) a square. 4

%I #12 Feb 12 2014 06:43:30

%S 0,1,2,2,3,2,2,2,1,1,1,1,2,2,1,1,1,2,4,4,4,4,5,5,5,5,4,3,5,4,5,4,4,4,

%T 4,3,4,3,4,4,4,3,4,3,3,3,4,3,3,3,2,2,4,3,3,2,2,2,4,4,5,4,4,4,3,2,3,2,

%U 3,3

%N Number of primes p <= n with floor( sqrt(n-p) ) a square.

%C Conjecture: a(n) > 0 for all n > 1, and a(n) = 1 only for n = 2, 9, 10, 11, 12, 15, 16, 17.

%C We have verified this for n up to 10^6.

%C See also A237705, A237706 and A237720 for similar conjectures.

%H Zhi-Wei Sun, <a href="/A237721/b237721.txt">Table of n, a(n) for n = 1..10000</a>

%e a(2) = 1 since 2 is prime with floor(sqrt(2-2)) = 0^2.

%e a(3) = 2 since 2 is prime with floor(sqrt(3-2)) = 1^2, and 3 is prime with floor(sqrt(3-3)) = 0^2.

%e a(9) = a(10) = 1 since 7 is prime with floor(sqrt(9-7)) = floor(sqrt(10-7)) = 1^2.

%e a(11) = 1 since 11 is prime with floor(sqrt(11-11)) = 0^2.

%e a(12) = 1 since 11 is prime with floor(sqrt(12-11)) = 1^2.

%e a(15) = a(16) = 1 since 13 is prime with floor(sqrt(15-13)) = floor(sqrt(16-13)) = 1^2.

%e a(17) = 1 since 17 is prime with floor(sqrt(17-17)) = 0^2.

%t SQ[n_]:=IntegerQ[Sqrt[n]]

%t q[n_]:=SQ[Floor[Sqrt[n]]]

%t a[n_]:=Sum[If[q[n-Prime[k]],1,0],{k,1,PrimePi[n]}]

%t Table[a[n],{n,1,70}]

%Y Cf. A000040, A000290, A237705, A237706, A237710, A237720.

%K nonn

%O 1,3

%A _Zhi-Wei Sun_, Feb 12 2014

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