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A232295 T(n,k)=Number of nXk 0..2 arrays with every 0 next to a 1 and every 1 next to a 2 horizontally or antidiagonally 14

%I #4 Nov 22 2013 07:21:55

%S 1,3,1,7,15,1,15,97,73,1,33,587,1313,355,1,73,3615,20563,17759,1727,1,

%T 161,22387,336079,718483,240241,8401,1,355,138505,5546705,31119789,

%U 25116353,3249889,40867,1,783,856719,91293443,1370434057,2885285507

%N T(n,k)=Number of nXk 0..2 arrays with every 0 next to a 1 and every 1 next to a 2 horizontally or antidiagonally

%C Table starts

%C .1......3..........7.............15.................33.....................73

%C .1.....15.........97............587...............3615..................22387

%C .1.....73.......1313..........20563.............336079................5546705

%C .1....355......17759.........718483...........31119789.............1370434057

%C .1...1727.....240241.......25116353.........2885285507...........339565321435

%C .1...8401....3249889......877968487.......267483142619.........84130295708483

%C .1..40867...43963319....30690409685.....24797475083765......20843967523877175

%C .1.198799..594719777..1072818688305...2298890419506403....5164265865545602229

%C .1.967065.8045152705.37501616113029.213122398219612007.1279489656786836660869

%H R. H. Hardin, <a href="/A232295/b232295.txt">Table of n, a(n) for n = 1..199</a>

%F Empirical for column k:

%F k=1: a(n) = a(n-1)

%F k=2: a(n) = 4*a(n-1) +4*a(n-2) +a(n-3)

%F k=3: a(n) = 12*a(n-1) +20*a(n-2) +9*a(n-3)

%F k=4: [order 10]

%F k=5: [order 13] for n>14

%F k=6: [order 37] for n>38

%F Empirical for row n:

%F n=1: a(n) = 2*a(n-1) +a(n-3)

%F n=2: [order 9]

%F n=3: [order 31]

%e Some solutions for n=3 k=4

%e ..2..2..2..1....2..1..2..2....0..1..0..1....2..2..2..2....1..2..1..0

%e ..2..1..0..0....1..2..2..1....2..2..2..0....1..1..2..0....2..0..2..2

%e ..0..0..1..2....1..0..2..2....2..2..1..2....2..2..1..2....2..2..1..0

%Y Row 1 is A193641

%K nonn,tabl

%O 1,2

%A _R. H. Hardin_, Nov 22 2013

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Last modified April 24 04:14 EDT 2024. Contains 371918 sequences. (Running on oeis4.)