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%I #26 Jan 02 2023 12:30:49
%S 1,1,1,1,1,1,2,1,1,1,1,1,2,4,1,1,1,1,1,2,1,1,2,4,8,1,1,1,1,1,2,1,1,2,
%T 4,1,1,2,4,8,16,1,1,1,1,1,2,1,1,2,4,1,1,2,4,8,1,1,2,4,8,16,32,1,1,1,1,
%U 1,2,1,1,2,4,1,1,2,4,8,1,1,2,4,8,16,1,1,2,4,8,16,32,64
%N Table read by rows: Replace last term of the n-th row with 1,1,2,4,...,2^n to get the next row.
%C Suggested (without definition) by A. Groeneveld in reply to a question on the SeqFan list.
%C The "limiting row" is given by A232089.
%C The diagonal T(i, i) also tends to A232089. - _Michel Marcus_, Dec 22 2014
%H A. Groeneveld, <a href="http://list.seqfan.eu/oldermail/seqfan/2014-January/012308.html">Re: guess the relation</a>, SeqFan mailing list, Jan. 2014.
%e The table goes like:
%e (row n=0) 1
%e (row n=1) 1, 1
%e (row n=2) 1, 1, 1, 2
%e (row n=3) 1, 1, 1, 1, 1, 2, 4
%e (row n=4) 1, 1, 1, 1, 1, 2, 1, 1, 2, 4, 8
%e (row n=5) 1, 1, 1, 1, 1, 2, 1, 1, 2, 4, 1, 1, 2, 4, 8, 16
%o (PARI) list_A232088(nRows,a=[1])=for(i=1,nRows,print(a);a[#a]=vector(i+1,j,max(2^(j-2),1));a=concat(a));a
%Y Row lengths are A000124(n)=n(n+1)/2+1.
%K nonn,easy,tabf
%O 0,7
%A _M. F. Hasler_, Jan 20 2014
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