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%I #10 Nov 05 2013 14:59:56
%S 1,3,10,24
%N Numbers n such that the total number of digits of all the divisors of n written in base 2 is equal to n.
%C Sequence is finite with 4 terms.
%C Numbers n such that the concatenation of their divisors written in base 2 contains n digits.
%C Subsequence of finite sequence: 1, 2, 3, 4, 6, 8, 10, 12, 24 (numbers n such that the total number of digits of all the divisors of n written in base 2 is greater than or equal to n).
%C Numbers n such that A182627(n) = n.
%e 24 is in the sequence because the concatenation of the divisors of 24 in base 2 [(1, 10, 11, 100, 110, 1000, 1100, 11000) -> 110111001101000110011000] contains 24 digits.
%Y Cf. A182622, A182627.
%K nonn,base,fini,full,less
%O 1,2
%A _Jaroslav Krizek_, Nov 03 2013
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