A231116 - OEIS

%I #10 Nov 05 2013 14:59:56

%S 1,3,10,24

%N Numbers n such that the total number of digits of all the divisors of n written in base 2 is equal to n.

%C Sequence is finite with 4 terms.

%C Numbers n such that the concatenation of their divisors written in base 2 contains n digits.

%C Subsequence of finite sequence:  1, 2, 3, 4, 6, 8, 10, 12, 24 (numbers n such that the total number of digits of all the divisors of n written in base 2 is greater than or equal to n).

%C Numbers n such that A182627(n) = n.

%e 24 is in the sequence because the concatenation of the divisors of 24 in base 2 [(1, 10, 11, 100, 110, 1000, 1100, 11000) -> 110111001101000110011000] contains 24 digits.

%Y Cf. A182622, A182627.

%K nonn,base,fini,full,less

%O 1,2

%A _Jaroslav Krizek_, Nov 03 2013