OFFSET
2,1
COMMENTS
a(9) = ( 4^5468 + 2*4^12 + 39 ) / 3.
a(10) = 4^5468 + 13.
a(11) = ( 4^10924 + 2*4^5468 + 16407 ) / 3.
a(12) = 4^10924 + 10925
a(13) = ( 4^5597880 + 3*4^10924 + 32793 ) / 3.
a(14) = ( 2*4^5597880 + 32812 ) / 3.
a(15) = ( 4^16777229 + 4^5597880 + 2*4^12 + 16427 ) / 3.
a(16) = ( 2*4^16777229 + 4^13 + 42 ) / 3.
LINKS
Max Alekseyev, Table n, expression for a(n) for n=2..100
Max A. Alekseyev and N. J. A. Sloane, On Kaprekar's Junction Numbers, arXiv:2112.14365, 2021; Journal of Combinatorics and Number Theory 12:3 (2022), 115-155.
CROSSREFS
KEYWORD
nonn,base
AUTHOR
N. J. A. Sloane, Oct 31 2013
EXTENSIONS
Terms a(8) onward from Max Alekseyev, Oct 31 2013
STATUS
approved