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 A227052 a(n) = (n^2)! / (n^2-n)! = number of ways of placing n labeled balls into n^2 labeled boxes with at most one ball in each box. 0

%I

%S 1,1,12,504,43680,6375600,1402410240,432938943360,178462987637760,

%T 94670977328928000,62815650955529472000,50963773003971232204800,

%U 49633807532904958383820800,57141374006987657125324185600,76763145767753986733306290176000,119005648371962652004288345681920000

%N a(n) = (n^2)! / (n^2-n)! = number of ways of placing n labeled balls into n^2 labeled boxes with at most one ball in each box.

%t Table[(n^2)!/(n^2-n)!,{n,0,20}] (* _Harvey P. Dale_, Aug 10 2017 *)

%o (Python)

%o import math

%o for n in range(20):

%o print str(math.factorial(n*n)/math.factorial(n*n-n))+',',

%Y Cf. A014062.

%K nonn,easy

%O 0,3

%A _Alex Ratushnyak_, Jun 29 2013

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Last modified December 5 12:42 EST 2022. Contains 358586 sequences. (Running on oeis4.)