%I #17 Feb 12 2024 10:17:29
%S 1,4562499,20816392562501,94974749433621124999,
%T 433322104341376699173125001,1977031234413227532474550849687499,
%U 9020201052947448468355731925898341687501,41154649263668650710741676972914857601690249999
%N Positive solutions x/(2^2*3*89) of the Pell equation x^2 - 73*y^2 = -1.
%C The proper positive solutions of the Pell equation x^2 - 73*y^2 = -1 start with the fundamental solution (x_0, y_0) = (1068, 125). 1068 = 2^2*3*89, 125 = 5^3. The solutions y(n)/5^3 = A227040(n), n>=0.
%D T. Nagell, Introduction to Number Theory, Chelsea Publishing Company, New York, 1964, ch. Vi, 58., p. 204-212.
%H Harvey P. Dale, <a href="/A227039/b227039.txt">Table of n, a(n) for n = 0..150</a>
%H <a href="/index/Ch#Cheby">Index entries for sequences related to Chebyshev polynomials.</a>
%H <a href="/index/Rec#order_02">Index entries for linear recurrences with constant coefficients</a>, signature (4562498,-1).
%F a(n) = S(n,4562498) + S(n-1,4562498), n >= 0, with the Chebyshev S-polynomials (A049310), with S(-1,x) = 0. 4562498 = 2*2281249 is the fundamental (improper) u solution of u^2 - 73*v^3 = +4 (together with the positive v = 53400 = 2*26700).
%F O.g.f.: (1 + x)/(1 - 4562498*x + x^2).
%F a(n) = 4562498*a(n-1) - a(n-2), n >= 1, a(-1) = -1, a(0) = 1.
%e n=0: (2^2*3*89*1)^2 - 73*(5^3*1)^2 = -1.
%e n=1: (2^2*3*89*4562499)^2 - 73*(5^3*4562497)^2 = -1. 4562499 = 3*67*22699. 4562497 is prime.
%t LinearRecurrence[{4562498,-1},{1,4562499},10] (* _Harvey P. Dale_, Mar 17 2019 *)
%Y Cf. A227040, A049310.
%K nonn,easy
%O 0,2
%A _Wolfdieter Lang_, Jun 28 2013
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