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 A226570 a(n) = Sum_{k=1..n} (k+1)! mod n. 1
 0, 0, 2, 0, 2, 2, 4, 0, 8, 2, 10, 8, 8, 4, 2, 8, 11, 8, 7, 12, 11, 10, 19, 8, 12, 8, 8, 4, 15, 2, 0, 24, 32, 28, 32, 8, 3, 26, 8, 32, 2, 32, 14, 32, 17, 42, 16, 8, 46, 12, 11, 8, 11, 8, 32, 32, 26, 44, 26, 32, 20, 0, 53, 24, 47, 32, 63, 28, 65, 32, 66, 8, 53, 40, 62, 64, 32, 8, 18, 72, 62, 2, 25, 32, 62, 14, 44, 32, 74, 62, 60, 88, 62, 16, 7, 56, 78, 46, 98 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,3 COMMENTS Motivated by sequence A100083, numbers such that a(n) = 0. - Hasler Note that this is a different sequence from A086330: in this one, the factorials are added up and then the remainder of the total divided by n is taken, whereas in A086330 each factorial is computed modulo n prior to being added up. - Alonso del Arte, Jun 11 2013 LINKS Charles R Greathouse IV, Table of n, a(n) for n = 1..10000 FORMULA a(n) = A086330(n) mod n. - Chai Wah Wu, Apr 16 2024 a(n) = Sum_{k=1..A002034(n)-2} (k+1)! mod n. - David A. Corneth, Apr 16 2024 EXAMPLE a(3) = 2 because 2!, 3! and 4! are 2, 6 and 24 respectively, which add up to 32, and modulo 3 that is 2. a(4) = 0 because 2!, 3!, 4! and 5! add up to 152, and modulo 4 that is 0 (note that this is different from A086330(4) = 4. MATHEMATICA Table[Mod[Sum[(k + 1)!, {k, n}], n], {n, 75}] (* Alonso del Arte, Jun 11 2013 *) PROG (PARI) a(n)=lift(sum(m=2, n-1, Mod(m!, n))) (PARI) a(n)=my(t=Mod(1, n)); lift(sum(m=2, n+1, t*=m)) \\ Charles R Greathouse IV, Jun 11 2013 (Python) def A226570(n): a, c = 0, 1 for m in range(2, n): c = c*m%n if c==0: break a = (a+c)%n return a # Chai Wah Wu, Apr 16 2024 CROSSREFS Cf. A002034, A086330, A100083, A007489, A003422. Sequence in context: A029906 A094907 A343401 * A158380 A051734 A157898 Adjacent sequences: A226567 A226568 A226569 * A226571 A226572 A226573 KEYWORD nonn AUTHOR M. F. Hasler, Jun 11 2013 STATUS approved

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Last modified July 12 11:27 EDT 2024. Contains 374245 sequences. (Running on oeis4.)