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A226056
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a(n) = Number of common trailing terms on the row n of tables A225632 and A225642.
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10
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1, 1, 1, 2, 2, 2, 3, 2, 2, 3, 3, 3, 3, 5, 1, 1, 2, 4, 1, 5, 2, 2, 4, 5, 2, 2, 1, 2, 4, 6, 1, 5, 2, 4, 1, 4, 3, 5, 1, 4, 1, 7, 6, 8, 4, 4, 4, 9, 3, 2, 1, 5, 4, 9, 2, 2, 2, 3, 2, 8, 6, 9, 1, 1, 1, 2, 4, 8, 3, 1, 4, 7, 8, 8, 2, 3, 3, 3, 1, 8, 1, 2, 3, 10, 10
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OFFSET
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0,4
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COMMENTS
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The positions n, in which a(n)=1: 0, 1, 2, 14, 15, 18, 26, 30, 34, 38, 40, 50, 62, 63, 64, 69, 78, 80, ...
By convention, a(0)=1 as this applies also to the tables A225630 and A225640, whose columns start from zero.
In other words, a(n) = 1 + distance from the first common term on column n (A226055(n)) of tables A225630 and A225640 to the respective fixed point, A003418(n).
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LINKS
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Table of n, a(n) for n=0..84.
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FORMULA
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a(n) = A225634(n)-A225638(n) = A225644(n)-A225639(n).
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EXAMPLE
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Row 7 of A225632 is:
1, 12, 84, 420;
Row 7 of A225642 is:
7, 84, 420;
the last two terms (84 and 420) are common to them, thus a(7)=2.
Row 14 of A225632 is:
1, 84, 1260, 16380, 180180, 360360;
Row 14 of A225642 is:
14, 630, 8190, 90090, 360360;
they have no common term until as the last term of those rows (which is A003418(14)=360360), thus a(14)=1.
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PROG
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(Scheme):
(define (A226056 n) (- (A225634 n) (A225638 n)))
(define (A226056 n) (- (A225644 n) (A225639 n))) ;; Alternative definition.
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CROSSREFS
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Cf. A226055, A225634, A225644, A225638, A225639.
Sequence in context: A129654 A116504 A186233 * A104011 A242879 A176775
Adjacent sequences: A226053 A226054 A226055 * A226057 A226058 A226059
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KEYWORD
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nonn
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AUTHOR
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Antti Karttunen, May 24 2013
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STATUS
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approved
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