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A220465 Reverse reluctant sequence of reverse reluctant sequence A004736. 1

%I #20 Feb 16 2022 11:59:04

%S 1,2,1,1,2,1,3,1,2,1,2,3,1,2,1,1,2,3,1,2,1,4,1,2,3,1,2,1,3,4,1,2,3,1,

%T 2,1,2,3,4,1,2,3,1,2,1,1,2,3,4,1,2,3,1,2,1,5,1,2,3,4,1,2,3,1,2,1,4,5,

%U 1,2,3,4,1,2,3,1,2,1,3,4,5,1,2,3,4,1,2,3,1,2,1,2,3,4,5,1,2,3,4,1,2,3,1,2,1,1,2,3,4,5,1,2,3,4,1,2,3,1,2,1,6,1,2,3

%N Reverse reluctant sequence of reverse reluctant sequence A004736.

%C Sequence B is called a reluctant sequence of sequence A, if B is triangle array read by rows: row number k coincides with first k elements of the sequence A.

%C Sequence B is called a reverse reluctant sequence of sequence A, if B is triangle array read by rows: row number k lists first k elements of the sequence A in reverse order.

%C Sequence A004736 is the reverse reluctant sequence of sequence 1,2,3,... (A000027).

%H Boris Putievskiy, <a href="/A220465/b220465.txt">Rows n = 1..140 of triangle, flattened</a>

%H Boris Putievskiy, <a href="http://arxiv.org/abs/1212.2732">Transformations Integer Sequences And Pairing Functions</a>, arXiv:1212.2732 [math.CO], 2012.

%F T(n,k) = A004736(n-k+1).

%F As a linear array, the sequence is a(n) = (t1*t1+3*t1+4)/2-n1, where n1=(t*t+3*t+4)/2-n, t1=floor[(-1+sqrt(8*n1-7))/2], t=floor[(-1+sqrt(8*n-7))/2].

%e The start of the sequence as triangle array T(n,k) is:

%e 1;

%e 2,1;

%e 1,2,1;

%e 3,1,2,1;

%e 2,3,1,2,1;

%e 1,2,3,1,2,1;

%e ...

%o (Python)

%o t=int((math.sqrt(8*n-7) - 1)/ 2)

%o n1=(t*t+3*t+4)/2-n

%o t1=int((math.sqrt(8*n1-7) - 1)/ 2)

%o m=(t1*t1+3*t1+4)/2-n1

%Y Cf. A000027, A004736, A002260, A220280.

%K easy,nonn,tabl

%O 1,2

%A _Boris Putievskiy_, Dec 15 2012

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