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A220448 Define a sequence u(n) by u(1)=1; thereafter u(n) = f(n)/f(n-1) where f(n) = (-1)^(n+1)*A105750(n); sequence gives numerator(u(n)). 3

%I #13 Aug 09 2023 12:39:23

%S 1,1,-10,-1,19,-73,662,-2795,281,-4511,21746,-322921,1035215,-720817,

%T 1077518,-87995911,-34376687,929280875,-92673902,6986985769,

%U -33833494045,243540693677,-1817775985570,13097400661955,-27199287430171,8249498995171439,-112427012362483262,3008079144099400625,-10365435567354511181

%N Define a sequence u(n) by u(1)=1; thereafter u(n) = f(n)/f(n-1) where f(n) = (-1)^(n+1)*A105750(n); sequence gives numerator(u(n)).

%C Also u(n) = n*x(n-1)-1, where x(n) is defined in A220447.

%H V. H. Moll, <a href="http://www.tulane.edu/~vhm/papers_html/xn-final.pdf">An arithmetic conjecture on a sequence of arctangent sums</a>, 2012.

%e The sequence u(n) begins 1, 1, -10, -1, 19, -73/19, 662/73, -2795/331, 281/43, -4511/281, 21746/4511, ...

%p A220448 := proc(n)

%p if n= 1 then

%p 1 ;

%p else

%p -A105750(n)/A105750(n-1) ;

%p numer(%) ;

%p end if;

%p end proc: # _R. J. Mathar_, Jan 04 2013

%t x[n_] := x[n] = If[n == 1, 1, (x[n-1] + n)/(1 - n*x[n-1])];

%t u[n_] := If[n == 1, 1, n*x[n-1] - 1];

%t a[n_] := Numerator[u[n]];

%t Table[a[n], {n, 1, 29}] (* _Jean-François Alcover_, Aug 09 2023 *)

%Y Denominator(u(n)) = A220447(n-1).

%K sign,frac

%O 1,3

%A _N. J. A. Sloane_, Dec 22 2012

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Last modified April 25 11:39 EDT 2024. Contains 371969 sequences. (Running on oeis4.)