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Sum of successive absolute differences of the binomial coefficients = 2*A014495(n)
1

%I #6 Nov 01 2012 11:21:06

%S 0,0,2,4,10,18,38,68,138,250,502,922,1846,3430,6862,12868,25738,48618,

%T 97238,184754,369510,705430,1410862,2704154,5408310,10400598,20801198,

%U 40116598,80233198,155117518,310235038

%N Sum of successive absolute differences of the binomial coefficients = 2*A014495(n)

%F a(n) = sum |C(n,k+1)-C(n,k)|, k=0..n-1 = 2*sum C(n,k+1)-C(n,k), k=0..floor((n-1)/2) = 2*(C(n, floor((n+1)/2)) - 1)

%o (Maxima) A218008(n):=2*(binomial(n,floor((n+1)/2))-1)$

%o makelist(A218008(n),n,0,30); /* _Martin Ettl_, Nov 01 2012 */

%Y Cf. Row sums of absolute values of A214292

%K nonn

%O 0,3

%A _Olivier GĂ©rard_, Oct 18 2012