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%I #7 Aug 26 2012 11:26:38
%S 48,630,4830,3513510,137507370
%N a(n) = least number m of A191837 for which the product of the first n+1 primes divides m.
%C Related to Goldbach partitions and primorials.
%e a(1) = 48, because 48 is the least number found in A191837 which is divisible by 2*3.
%e a(2) = 630, because it is the least number found in A191837 which is divisible by 2*3*5.
%Y Cf. A191837
%K nonn,more
%O 1,1
%A _J. Stauduhar_, Aug 25 2012
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