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A213761 Rectangular array: (row n) = b**c, where b(h) = h, c(h) = 3*n-5+3*h, n>=1, h>=1, and ** = convolution. 5

%I #12 Feb 14 2014 04:13:25

%S 1,6,4,18,15,7,40,36,24,10,75,70,54,33,13,126,120,100,72,42,16,196,

%T 189,165,130,90,51,19,288,280,252,210,160,108,60,22,405,396,364,315,

%U 255,190,126,69,25,550,540,504,448,378,300

%N Rectangular array: (row n) = b**c, where b(h) = h, c(h) = 3*n-5+3*h, n>=1, h>=1, and ** = convolution.

%C Principal diagonal: A172073.

%C Antidiagonal sums: A002419.

%C Row 1, (1,2,3,4,5,...)**(1,4,7,10,13,...): A002411.

%C Row 2, (1,2,3,4,5,...)**(4,7,10,13,16,...): A077414.

%C Row 3, (1,2,3,4,5,...)**(7,10,13,16,...): (k^3 + 7*k^2 + 6*k)/2.

%C Row 4, (1,2,3,4,5,...)**(10,13,16,...): (k^3 + 10*k^2 + 9*k)/2.

%C For a guide to related arrays, see A212500.

%H Clark Kimberling, <a href="/A213761/b213761.txt">Antidiagonals n = 1..45, flattened</a>

%F T(n,k) = 4*T(n,k-1)-6*T(n,k-2)+4*T(n,k-3)-T(n,k-4).

%F G.f. for row n: f(x)/g(x), where f(x) = x*(3*n - 2 - (3*n - 5)*x) and g(x) = (1 - x)^4.

%e Northwest corner (the array is read by falling antidiagonals):

%e 1....6....18...40....75....126

%e 4....15...36...70....120...189

%e 7....24...54...100...165...252

%e 10...33...72...130...210...315

%e 13...42...90...160...255...378

%t b[n_]:=n;c[n_]:=3n-2;

%t t[n_,k_]:=Sum[b[k-i]c[n+i],{i,0,k-1}]

%t TableForm[Table[t[n,k],{n,1,10},{k,1,10}]]

%t Flatten[Table[t[n-k+1,k],{n,12},{k,n,1,-1}]]

%t r[n_]:=Table[t[n,k],{k,1,60}] (* A213761 *)

%t Table[t[n,n],{n,1,40}] (* A172073 *)

%t s[n_]:=Sum[t[i,n+1-i],{i,1,n}]

%t Table[s[n],{n,1,50}] (* A002419 *)

%Y Cf. A212500.

%K nonn,tabl,easy

%O 1,2

%A _Clark Kimberling_, Jul 04 2012

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