%I #11 Jan 28 2013 12:42:21
%S 6,8,5,1,4,2,4,1,5,8,6,4,1,1,4,6,8,5,1,4,2,4,1,5,8,6,4,1,1,4,6,8,5,1,
%T 4,2,4,1,5,8,6,4,1,1,4,6,8,5,1,4,2,4,1,5,8,6,4,1,1,4,6,8,5,1,4,2,4,1,
%U 5,8,6,4,1,1,4,6,8,5,1,4,2,4,1,5,8,6,4
%N a(n) is difference of indices of terms >= 6 in A187824.
%C The repeat cycle contains 15 numbers which have 9 Fibonacci number symmetrically distributed as below.
%C 1 F(1), F(2)
%C 4
%C 6
%C 8 F(6)
%C 5 F(5)
%C 1 F(1), F(2)
%C 4
%C 2 F(3)
%C 4
%C 1 F(1), F(2)
%C 5 F(5)
%C 8 F(6)
%C 6
%C 4
%C 1 F(1), F(2)
%e For A187824(m(i)) >= 6:
%e m(1) = 5, m(2) = 11, m(3) = 19,
%e ...
%e a(1) = 11 - 5 = 6, a(2) = 19 - 11 = 8,
%e ...
%Y Cf. A187824, A192129.
%K nonn,less
%O 1,1
%A _Kival Ngaokrajang_, Jan 16 2013