

A201221


The smallest number of previous terms of sequence A008829 which are required to sum to A008829(n).


0



4, 6, 8, 10, 12, 14, 16, 16, 19, 16, 18, 17, 19, 18, 28, 34, 72, 49, 57, 35, 51, 36, 97, 65, 56, 56, 57, 69, 64, 65, 219, 136, 96, 72, 79, 75, 78, 74, 78, 70, 72, 73
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OFFSET

2,1


LINKS



EXAMPLE

For n=2, the corresponding term of A008829 is 4, and the only preceding term is 1, therefore four 1s are needed and term a(2)=4.
Likewise, for n=3, the corresponding term is 15, which is three 4s and three 1s, so term a(3)=6.


CROSSREFS



KEYWORD

nonn,base,more


AUTHOR



EXTENSIONS



STATUS

approved



