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%I #5 Mar 31 2012 12:36:43
%S 0,0,0,0,0,0,0,1,1,0,0,6,8,6,0,0,24,45,45,24,0,0,80,225,276,225,80,0,
%T 0,239,1005,1742,1742,1005,239,0,0,665,4104,10723,13375,10723,4104,
%U 665,0,0,1756,15592,62507,104429,104429,62507,15592,1756,0,0,4459,55914,341239
%N T(n,k)=Number of nXk 0..2 arrays with every row and column running average nondecreasing rightwards and downwards but some diagonal running average having a decrease
%C Table starts
%C .0....0......0.......0.........0..........0............0.............0
%C .0....0......1.......6........24.........80..........239...........665
%C .0....1......8......45.......225.......1005.........4104.........15592
%C .0....6.....45.....276......1742......10723........62507........341239
%C .0...24....225....1742.....13375.....104429.......817653.......6227099
%C .0...80...1005...10723....104429.....994581......9782242......98775535
%C .0..239...4104...62507....817653....9782242....117867542....1504100224
%C .0..665..15592..341239...6227099...98775535...1504100224...23922555921
%C .0.1756..55914.1756705..45507712..992953397..20036576547..407696445449
%C .0.4459.191522.8615033.318531032.9709526788.268650529838.7294329757608
%H R. H. Hardin, <a href="/A201195/b201195.txt">Table of n, a(n) for n = 1..161</a>
%e Some solutions for n=4 k=7
%e ..0..0..0..0..2..1..2....0..0..0..0..0..0..0....0..0..0..0..0..0..1
%e ..0..0..0..1..2..1..2....0..0..2..1..2..1..1....0..2..2..2..2..2..2
%e ..0..0..1..2..2..1..2....0..0..1..2..1..1..2....0..1..1..2..1..2..2
%e ..0..0..1..1..2..1..2....0..0..1..2..1..1..1....0..1..1..2..1..2..2
%K nonn,tabl
%O 1,12
%A _R. H. Hardin_ Nov 28 2011