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A195319
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Three times second hexagonal numbers: 3*n*(2*n+1).
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5
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0, 9, 30, 63, 108, 165, 234, 315, 408, 513, 630, 759, 900, 1053, 1218, 1395, 1584, 1785, 1998, 2223, 2460, 2709, 2970, 3243, 3528, 3825, 4134, 4455, 4788, 5133, 5490, 5859, 6240, 6633, 7038, 7455, 7884, 8325, 8778, 9243, 9720, 10209, 10710, 11223
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OFFSET
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0,2
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COMMENTS
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Sequence found by reading the line from 0, in the direction 0, 9, ..., in the square spiral whose vertices are the generalized pentagonal numbers A001318. Semi-axis opposite to A094159 in the same spiral.
Also 0 together with the partial sums of A017629.
Digit root is 0 together with period 3: repeat [9,3,9].
Final digits cycle a length period 10: repeat [0,9,0,3,8,5,4,5,8,3]. (End)
Sequence found by reading the line from 0, in the direction 0, 9, ..., in the triangle spiral. - Hans G. Oberlack, Dec 08 2018
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LINKS
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FORMULA
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a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3) for n>2. - Harvey P. Dale, Oct 13 2013
Sum_{n>=1} 1/a(n) = 2*(1 - log(2))/3.
Sum_{n>=1} (-1)^(n+1)/a(n) = (Pi/2 + log(2) - 2)/3. (End)
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MAPLE
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MATHEMATICA
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Table[6n^2+3n, {n, 0, 50}] (* or *) LinearRecurrence[{3, -3, 1}, {0, 9, 30}, 50] (* Harvey P. Dale, Oct 13 2013 *)
CoefficientList[Series[3 x (3 + x)/(1 - x)^3, {x, 0, 50}], x] (* Wesley Ivan Hurt, Nov 27 2015 *)
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PROG
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(Sage) [3*n*(2*n+1) for n in range(50)] # G. C. Greubel, Dec 07 2018
(GAP) List([0..30], n -> 3*n*(2*n+1)); # G. C. Greubel, Dec 07 2018
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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